bars
📈
notes
search
circle-xmark
⌘
Ctrl
k
copy
Copy
chevron-down
1190_Reverse_Substrings_Between_Each_Pair_of_Parentheses
Solution1 模拟 + 栈
时间复杂度 O(n^2)
最坏情况,每个字符右边都有一个
)
空间复杂度 O(n)
Previous
1190_Reverse_Substrings_Between_Each_Pair_of_Parentheses
chevron-left
Next
1202_Smallest_String_With_Swaps
chevron-right
Last updated
4 years ago