# Solution 1 hash\_table, 利用3个二维数组一起检查

关键是理解如何把0-8 \* 0-8的91个方块放到0-8中

我们先看i = 6,7,8的情况，这时i/3*3=6，j/3=0,1,2 加上就是（678）最后一行的三个大方块的编号。同理i = 3,4,5时，i/3*3=3，加上j就是（345）第二行三个大方块的编号。同理i = 0,1,2时，i/3\*3=0，加上j/3就是（012）第一行三个大方块的编号。

i / 3 \* 3 后值为0,3,6 j / 3后值为0,1,2


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